4y^3x+2y^2v^2+4y=

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Solution for 4y^3x+2y^2v^2+4y= equation:


Simplifying
4y3x + 2y2v2 + 4y = 0

Reorder the terms:
2v2y2 + 4xy3 + 4y = 0

Solving
2v2y2 + 4xy3 + 4y = 0

Solving for variable 'v'.

Move all terms containing v to the left, all other terms to the right.

Add '-4xy3' to each side of the equation.
2v2y2 + 4xy3 + -4xy3 + 4y = 0 + -4xy3

Combine like terms: 4xy3 + -4xy3 = 0
2v2y2 + 0 + 4y = 0 + -4xy3
2v2y2 + 4y = 0 + -4xy3
Remove the zero:
2v2y2 + 4y = -4xy3

Add '-4y' to each side of the equation.
2v2y2 + 4y + -4y = -4xy3 + -4y

Combine like terms: 4y + -4y = 0
2v2y2 + 0 = -4xy3 + -4y
2v2y2 = -4xy3 + -4y

Divide each side by '2y2'.
v2 = -2xy + -2y-1

Simplifying
v2 = -2xy + -2y-1

Reorder the terms:
v2 + 2xy + 2y-1 = -2xy + 2xy + -2y-1 + 2y-1

Combine like terms: -2xy + 2xy = 0
v2 + 2xy + 2y-1 = 0 + -2y-1 + 2y-1
v2 + 2xy + 2y-1 = -2y-1 + 2y-1

Combine like terms: -2y-1 + 2y-1 = 0
v2 + 2xy + 2y-1 = 0

The solution to this equation could not be determined.

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